优化前：
c++
bool checkRecord(string s) {
int logA = 0;
for (int i=0; i<s.length(); i++) {
if (s[i]=='A') {
logA++;
if (logA>1) {
return 0;
}
}
if (i>1&&s[i]=='L'&&s[i-1]=='L'&&s[i-2]=='L') {
return 0;
}
}
return 1;
}


优化后：

class Solution {
public:
    bool checkRecord(string s) {
        int count_A = 0;
        int pos = 0;
        while(pos<s.length())
        {
            if(s[pos]=='A')
            {
                count_A++;
                pos++;
                if(count_A>1)
                    return false;
            }
            else if(s[pos]=='L')
            {
                int count = 0;
                while(pos<s.length()&&s[pos]=='L')
                {
                    count++;
                    pos++;
                }
                if(count>2)
                    return false;
            }
            else
                pos++;
            
        }
        return true;
    }
};